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Find out if string ends with another string in C

April 8, 2025

📂 Categories: C++
Find out if string ends with another string in C

Figuring out if a drawstring ends with a circumstantial suffix is a communal project successful C++ programming. Whether or not you’re validating person enter, parsing record paths, oregon running with matter information, businesslike suffix checking is indispensable for sturdy and performant codification. This article explores assorted strategies to accomplish this, ranging from constructed-successful features to customized implementations, and delves into their show concerns. Knowing these methods empowers you to take the about appropriate attack for your circumstantial wants and optimize your C++ drawstring manipulation operations.

Utilizing std::drawstring::ends_with() (C++20 and future)

The about simple attack for checking drawstring endings successful contemporary C++ is the ends_with() methodology launched successful C++20. This constructed-successful relation straight addresses the job and provides a cleanable, readable resolution. It returns actual if the drawstring ends with the specified suffix and mendacious other.

Illustration:

std::drawstring str = "Hullo, planet!";<br></br> bool endsWithWorld = str.ends_with("planet!"); // actual<br></br> bool endsWithHello = str.ends_with("Hullo"); // mendaciousThis methodology is extremely beneficial for its simplicity and readability if your compiler helps C++20 oregon future.

Utilizing std::drawstring::rfind() (C++eleven and future)

For tasks utilizing C++eleven oregon future however anterior to C++20, std::drawstring::rfind() gives an effectual alternate. This relation searches for the past incidence of a substring inside a drawstring. By looking for the suffix and checking if its assumption matches the extremity of the drawstring, you tin find if the drawstring ends with the fixed suffix.

Illustration:

std::drawstring str = "Filename.txt";<br></br> std::drawstring suffix = ".txt";<br></br> size_t pos = str.rfind(suffix);<br></br> bool endsWithSuffix = (pos != std::drawstring::npos) && (pos == str.dimension() - suffix.dimension());This attack is somewhat much analyzable however provides compatibility with a wider scope of C++ requirements.

Implementing a Customized ends_with() Relation

Successful any instances, peculiarly once running with older C++ requirements oregon specialised drawstring sorts, creating a customized ends_with() relation whitethorn beryllium essential. This supplies flexibility and power complete the implementation.

Illustration:

bool ends_with(const std::drawstring& str, const std::drawstring& suffix) {<br></br>   if (suffix.dimension() > str.dimension()) {<br></br>     instrument mendacious;<br></br>   }<br></br>   instrument str.substr(str.dimension() - suffix.dimension()) == suffix;<br></br> }This customized relation replicates the performance of the C++20 ends_with() technique and tin beryllium tailored to circumstantial task necessities.

Increase Room’s ends_with

The Enhance room, a wide utilized postulation of C++ libraries, offers its ain ends_with algorithm. This provides different alternate, peculiarly utile successful initiatives already leveraging Increase elements.

Illustration:

see <increase/algorithm/drawstring/predicate.hpp><br></br> std::drawstring str = "Illustration drawstring";<br></br> bool endsWithString = enhance::algorithm::ends_with(str, "drawstring");Using Enhance simplifies integration for tasks already utilizing the room and avoids the demand for customized implementations.

Selecting the correct methodology relies upon connected your C++ modular compatibility, task dependencies, and show necessities. For C++20 and past, std::drawstring::ends_with() is the advisable attack. Successful earlier requirements, std::drawstring::rfind() oregon a customized implementation supply viable options. The Increase room’s ends_with relation is besides an action for tasks already utilizing Enhance.

  • Prioritize std::drawstring::ends_with() once disposable.
  • See show implications once selecting a methodology.
  1. Place the mark C++ modular.
  2. Take the due methodology primarily based connected compatibility and show wants.
  3. Instrumentality and trial the chosen resolution.

For optimum show successful drawstring manipulation duties, particularly once dealing with ample datasets, see utilizing specialised drawstring libraries oregon algorithms designed for ratio.

Larn much astir drawstring manipulation strategies.Outer Sources:

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Often Requested Questions

Q: What is the clip complexity of std::drawstring::ends_with()?

A: Usually, the complexity is linear successful the dimension of the suffix.

Mastering these methods volition importantly better your quality to effectively procedure and analyse matter information successful C++. By knowing the nuances of all attack, you tin choice the champion technique for your task, making certain cleanable, maintainable, and advanced-performing codification. For additional exploration, see investigating specialised drawstring algorithms and information buildings for much precocious drawstring manipulation duties. Research further assets and deepen your C++ drawstring manipulation experience to compose much businesslike and effectual codification.

Question & Answer :
However tin I discovery retired if a drawstring ends with different drawstring successful C++?

Merely comparison the past n characters utilizing std::drawstring::comparison:

#see <iostream> bool hasEnding (std::drawstring const &fullString, std::drawstring const &ending) { if (fullString.dimension() >= ending.dimension()) { instrument (zero == fullString.comparison (fullString.dimension() - ending.dimension(), ending.dimension(), ending)); } other { instrument mendacious; } } int chief () { std::drawstring test1 = "binary"; std::drawstring test2 = "unary"; std::drawstring test3 = "tertiary"; std::drawstring test4 = "ry"; std::drawstring ending = "nary"; std::cout << hasEnding (test1, ending) << std::endl; std::cout << hasEnding (test2, ending) << std::endl; std::cout << hasEnding (test3, ending) << std::endl; std::cout << hasEnding (test4, ending) << std::endl; instrument zero; }